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Suppose that you have a supply of a 25% solution of alcohol and a 75% solution of alcohol. How many quarts of each should be mi...Asked by Chanelle
Suppose that you have a supply of a 25% solution of alcohol and a 75% solution of alcohol. How many quarts of each should be mixed to produce 90 quarts that is 60% alcohol?
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Answered by
Steve
work with the amount of alcohol in each part. It has to add up to the total alcohol.
.25x + .75(90-x) = .60(90)
x = 27
so, 27 qt @ 25% and 63 qt @ 75%
.25x + .75(90-x) = .60(90)
x = 27
so, 27 qt @ 25% and 63 qt @ 75%
Answered by
Chanelle
Thank you,and how did you get come up with the equation?
Answered by
Chanelle
Thank you,and how did set up the equation?
Answered by
Steve
If you let x be the amount of 25% solution, then .25x is the amount of alcohol in that solutions.
Since there are 90 qts in all, 90-x is the amount of the 75% solution. .75(90-x) is the amount of alcohol in that solution.
Add up the two amounts of alcohol, and it must equal the amount of alcohol in 90 qts of 60% solution.
Ta-daa
Since there are 90 qts in all, 90-x is the amount of the 75% solution. .75(90-x) is the amount of alcohol in that solution.
Add up the two amounts of alcohol, and it must equal the amount of alcohol in 90 qts of 60% solution.
Ta-daa
Answered by
Chanelle
Thanks
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