Asked by Thuy
During an experiment, a student adds 0.339 g of calcium metal to 100.0 mL of 2.05 M HCl. The student observes a temperature increase of 11.0 °C for the solution. Assuming the solutions' final volume is 100.0 mL, the density is 1.00 g/mL, and the specific heat is 4.184 J/(g·°C), calculate the heat of the reaction, ΔHrxn.
Answers
Answered by
DrBob222
q = mass H2O x specific heat H2O x delta T.
q give you the heat gained by the solution which is the heat of the reaction.
q/2.05 give heat in J/gram
(q/2.05)*40.08 gives delta H/mol.
q give you the heat gained by the solution which is the heat of the reaction.
q/2.05 give heat in J/gram
(q/2.05)*40.08 gives delta H/mol.
Answered by
Anonymous
I have a similar problem, but with different numbers. What did you end up getting for q?
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