At a certain temperature, the equilibrium

Question

constant Kc is 0.154 for the reaction
2 SO2(g) + O2(g) *) 2 SO3(g)
What concentration of SO3 would be in
equilibrium with 0.250moles of SO2 and 0.853
moles of O2 in a 1.00 liter container at this
temperature? Note: These latter moles are
the equilibrium values.
Answer in units of M

Answer 1

Since these mols are in 1.00L, mols = M.
.........2SO2 + O2 ==> 2SO3
E........0.250..0.853...x

Kc = (SO3)^2/(SO2)^2(O2)
Substitute and solve for x.

Answer 2

1.70M