Asked by Becky
Find a solution to the equation if possible. Give the answer in exact form and in decimal form rounded to three decimal places.
1=21tan(2x+2)-6
1=21tan(2x+2)-6
Answers
Answered by
oobleck
1=21tan(2x+2)-6
tan(2x+2) = 1/3
2x+2 = arctan(1/3)
x = (arctan(1/3) - 2)/2
tan(2x+2) = 1/3
2x+2 = arctan(1/3)
x = (arctan(1/3) - 2)/2
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