Question

i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;-31 c) 5 d) 31;-31

also sove check for extraneous solutions
(6x-5)^1/2 = (7+ 4x)^1/2
a) 1/6 b) -9 c) 6 or d) 1/5

Answer 1

(x + 4)^2/3= 9
[(x + 4)^2/3]^(3/2)= 9^(3/2)

x+4 = 27
x = 23

do the second one by squaring both sides

Answer 2

ok so for this one i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;-31 c) 5 d) 31;-31
it would be c 23 or -31 right?
for for the 2nd one i got -9?
but i don't think i did it right