1/do +1/di =1/f
f= - 0.6 m (for diverging lens), do= 1.5 m
1/di=-1/do+1/f=-(1/1.5+1/0.6)=2.33
di= - 0.43 m (‘-‘ as the image is in front of the lens)
Magnification M= - di/do=0.43/1.5=0.287
h=M•H=0.287•10=2.87 cm
A near-sighted person might correct his vision by wearing diverging lenses with focal length f = 60 cm. When wearing his glasses, he looks not at actual objects but at the virtual images of those objects formed by his glasses. Suppose he looks at a 10-cm-long pencil held vertically 1.5 m from his glasses. WHAT IS THE HEIGHT?
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