A 0.10 kilogram ball dropped vertically from a height of 1.0 meter above the floor bounces back to a height of 0.80 meter. The mechanical energy lost by the ball as it bounces is aprox.

Question

a. 0.080 J
b. 0.20 J
c. 0.30 J
d. 0.78 J

Answer 1

E=mgh1-mgh2=mg(h1-h2)=
=0.1•9.8(1-0.8)=0.78 J

Answer 2

B.) (.10kg)(10 m/s^2)(0.20m) = .20J

Answer 3

.20