Asked by Tessa
Suppose the battery on your phone delivers a current of 0.740 mA (that's milliAmperes) over a time of 4.00 hours. What is the total charge that flows out of the battery during this time?
AND
How many electrons flow out of the battery during this time?
AND
How many electrons flow out of the battery during this time?
Answers
Answered by
Elena
I=q/t =>
q=It=0.74•10⁻³•4•3600=10.66 C,
N=q/e=10.66/1.6•10⁻¹⁹=6.66•10¹⁹
q=It=0.74•10⁻³•4•3600=10.66 C,
N=q/e=10.66/1.6•10⁻¹⁹=6.66•10¹⁹
Answered by
RAYMOND OCHIMA
what law of vectors
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