find the derivative of:
g(x) = interal(a=7x, b=6x) (u+5)/(u-5) du
Hint:
interal(a=7x, b=6x) (u+5)/(u-5) du
= interal(a=0, b=6x) (u+5)/(u-5) du + interal(a=7x, b=0) (u+5)/(u-5) du
3 answers
it's integral, not interal, sorry for the mistake
Using Leibnitz's integral rule,
d/dx ∫[7x,6x] (u+5)/(u-5) du
= 6*(6x+5)/(6x-5) - 7*(7x+5)/(7x-5)
= 60/(6x-5) - 70/(7x-5) - 1
d/dx ∫[7x,6x] (u+5)/(u-5) du
= 6*(6x+5)/(6x-5) - 7*(7x+5)/(7x-5)
= 60/(6x-5) - 70/(7x-5) - 1
Thank Steve. But how do you get 60 or 70?
or the -1?
or the -1?