In the chlor-alkali process, the mass of NaCl(s) required to produce 0.793 kg of chlorine gas is _____ kg.

Answer 1

The process reaction is:
2 NaCl + 2 H2O -> 2NaOH + H2 + Cl2

Convert 793 g of Cl2 to moles. It is about 11.17 moles.

You will need twice as many moles of NaCl. Convert that number to mass of NaCl, in the usual manner.

Answer 2

http://en.wikipedia.org/wiki/Chloralkali_process