Asked by Allan
In the chlor-alkali process, the mass of NaCl(s) required to produce 0.793 kg of chlorine gas is _____ kg.
Answers
Answered by
drwls
The process reaction is:
2 NaCl + 2 H2O -> 2NaOH + H2 + Cl2
Convert 793 g of Cl2 to moles. It is about 11.17 moles.
You will need twice as many moles of NaCl. Convert that number to mass of NaCl, in the usual manner.
2 NaCl + 2 H2O -> 2NaOH + H2 + Cl2
Convert 793 g of Cl2 to moles. It is about 11.17 moles.
You will need twice as many moles of NaCl. Convert that number to mass of NaCl, in the usual manner.
Answered by
drwls
http://en.wikipedia.org/wiki/Chloralkali_process
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