Question
If the probability that a certain tennis player will serve an ace is 1/4, what is the probability that he will serve exactly two aces out of four serves? (Assume that the four serves are independent. Round your answer to four decimal places.)
Answers
I guess I will have to use binomial coefficients.
the probability of k successes in n trials is:
P(k) = C(n,k) p^k (1-p)^(n-k)
C(n,k) is binomial coef
get from Pascal triangle or table or calculate from
C(n,k) - n! / [ k! (n-k)! ]
here
p = prob of ace = .25
(1-p) = .75
n = 4
k = 2
C(4,2) = 4! /[2!(2!)] = 4*3*2/[2(2)] = 6
so
P(2) = 6 (.25)^2 (.75)^2
= .21
the probability of k successes in n trials is:
P(k) = C(n,k) p^k (1-p)^(n-k)
C(n,k) is binomial coef
get from Pascal triangle or table or calculate from
C(n,k) - n! / [ k! (n-k)! ]
here
p = prob of ace = .25
(1-p) = .75
n = 4
k = 2
C(4,2) = 4! /[2!(2!)] = 4*3*2/[2(2)] = 6
so
P(2) = 6 (.25)^2 (.75)^2
= .21
Related Questions
A tennis player makes a successful first serve 51% of the time. if she serves 9 times, what is the p...
Given the probability that a certain tennis player will serve an ace is 1/4 and serves 5 times.
a) w...
1) If the probability that a tennis player will serve an ace is .27, what is the probability that he...
Consider the situations below. Which of these is the BEST example of Newton's 1st Law (inertia)? (1...