Asked by Jeremy
For the oxidation of glucose ( C6H12O6 + 2O2---6H2O +6CO2), how many moles of O2 will it take to consume 6 moles of glucose. Can someone explain it?
Answers
Answered by
Aparna
12, because there is 1 mole of c6h12o6 and 2 moles of o2 so you have a 1:2 ratio
Answered by
DrBob222
In chemistry you can, with the help of a balanced chemical equation, convert anything to anything. The coefficients in the balanced equation are used for that purpose. First, the equation you wrote is not balanced. The proper equation is
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
?mols O2 = 6 mols glucose x (6 mols O2/1 mol glucose) = 6*(6/1) = 36 mols O2.
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
?mols O2 = 6 mols glucose x (6 mols O2/1 mol glucose) = 6*(6/1) = 36 mols O2.
Answered by
Q
The answer is 36
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