Question

How would you solve the following I'm stumped..
1. 2x^2(squared)=30-4x
2. X^3(cubed)+8x=-6x^2(squared)

Thanks!

Answer 1

First, set each equation equal to 0:

1. 2x^2 + 4x - 30 = 0

2. x^3 + 6x^2 + 8x = 0

Try to factor when possible:

1. (2x - 6)(x + 5) = 0

2. x(x^2 + 6x + 8) = 0
x(x + 2)(x + 4) = 0

Set each factor equal to 0:

1. 2x - 6 = 0
x + 5 = 0

2. x = 0
x + 2 = 0
x + 4 = 0

Can you take it from here to find the solutions for x in both problems?

I hope this explanation helps.

Answer 2

Yes thank you!