A = LW
125 = 25 * 5
P = 2L + 2W
P = 50 + 10
P = 60 feet
125 = 25 * 5
P = 2L + 2W
P = 50 + 10
P = 60 feet
P=250 + 50 =300
Let's assume the width of the rectangle is "w".
According to the given information, the length of the rectangle is 5 times the width. Therefore, the length can be represented as "5w".
The formula to calculate the area of a rectangle is A = length * width.
In this case, the area is given as 125 square feet. So we can write the equation as:
125 = 5w * w
Now, we can solve this equation to find the width, "w":
125 = 5w^2
Divide both sides by 5:
25 = w^2
Taking the square root of both sides:
w = √25
So, the width of the rectangle is 5 feet.
Now, we can find the length of the rectangle:
Length = 5w = 5 * 5 = 25 feet.
To find the perimeter of the rectangle:
Perimeter = 2 * (length + width)
= 2 * (25 + 5)
= 2 * 30
= 60 feet.
Therefore, the perimeter of the rectangle is 60 feet.