Asked by Riana
                (2-√2)/(3+√2)
can you plz tell me how to solve it? plz hurry up
            
        can you plz tell me how to solve it? plz hurry up
Answers
                    Answered by
            Riana
            
    for god sake plz help me.
    
                    Answered by
            Febamol Babu
            
    i think the answer may be this
(2-√2)/(3+√2)
(2-√2)(3-√2)/(3+√2)(3-√2)
6-2√2-3√2+2/3*3-√2*√2
8-5√2/9-2
8-5√2/7
2√2-5√2/7
=-3√2/7
        
    
(2-√2)/(3+√2)
(2-√2)(3-√2)/(3+√2)(3-√2)
6-2√2-3√2+2/3*3-√2*√2
8-5√2/9-2
8-5√2/7
2√2-5√2/7
=-3√2/7
                    Answered by
            Reiny
            
    (2-√2)/(3+√2) 
=(2-√2)/(3+√2) * (3-√2)/(3-√2)
= (6 -2√2 - 3√2 + 2)/(9-2)
= (8 - 5√2)/7
    
=(2-√2)/(3+√2) * (3-√2)/(3-√2)
= (6 -2√2 - 3√2 + 2)/(9-2)
= (8 - 5√2)/7
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