Asked by Anonymous
What is the limit?
1. limit as x goes to POSITIVE infinity
(10x+8)/(7x^2-3x+5)
2. as x goes to NEGATIVE infinity
(10x+8)/(7x^2-3x+5)
1. limit as x goes to POSITIVE infinity
(10x+8)/(7x^2-3x+5)
2. as x goes to NEGATIVE infinity
(10x+8)/(7x^2-3x+5)
Answers
Answered by
Damon
10 x/7x^2 -->10/7x ---> oo
-10 |x | /7 |x|^2 --> -10/7 |x| --> -oo
-10 |x | /7 |x|^2 --> -10/7 |x| --> -oo
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