Question

The displacement (in meters) of a particle moving in a straight line is given by s=2t^3 where is measured in seconds. Find the average velocity of the particle over the time interval [10,13].

the average velocity is 798

What is the instantaneous velocity of the particle when t=10?

Answer 1

distance gone during seconds 10, 11, and 12 /3
s(13) = 4394
s(10) = 2000
distance = 2394
av speed = 2394/3 = 798 m/s

ds/dt = v = 6 t^2
v(10) = 6 (100) = 600 m/s

Answer 2

444m/s