Question

Given the following reaction:
3 CaCl2 + 2 H3PO4 Ca3(PO4)2 + 6 HCl
How many grams of H3PO4 are needed to react completely with 1.837 g of CaCl2?

I don't understand at all

Answer 1

cmon, we just did one of these. convert grams to moles, then use the reaction to figure the relative amounts needed/produced.

moles of input = 1.837/111 = .01655 moles CaCl2

Each 3 CaCl2 requires 2 H3PO4

so, 2/3 * .01655 = .011 moles H3PO4

.011 moles H3PO4 = .011 * 98 = 1.081g

Answer 2

3 CaCl2 + 2 H3PO4 Ca3(PO4)2 + 6 HCl
How many moles of HCl will be produced if 3.525 g of H3PO4 are reacted completely?

Answer 3

H3POA(1) + CaCh(aq) =Cag(POA)2(s) + HC1 (ag)
A. How many moles of calcium chloride are required to react to produce 0.873 moles
of calcium phosphate?
B. How many moles of phosphoric acid are required to react with 2.14 moles of
calcium chloride?