Asked by Nat
I have a maths exam tomorrow and am studying with a friend. We are working on a question and are getting two different answers. Could you please show us the right way to do it?
2(4x + 3)(4x - 3) - (4x + 3)squared
p.s i couldn't find a squared symbol so only the last bracket is squared, not the whole equation.
2(4x + 3)(4x - 3) - (4x + 3)squared
p.s i couldn't find a squared symbol so only the last bracket is squared, not the whole equation.
Answers
Answered by
Reiny
2(4x + 3)(4x - 3) - (4x + 3)squared
we usually write it this way
2(4x + 3)(4x - 3) - (4x + 3)^2
= 2(16x^2 - 9) - (4x + 3)(4x + 3)
= 2(16x^2 - 9) - (16x^2 + 24x + 9)
= 32x^2 - 18 - 16x^2 - 24x - 9
= 16x^2 24x - 27
or you could take out a common factor from
2(4x + 3)(4x - 3) - (4x + 3)^2
= (4x + 3)(2(4x-3) - (4x+3))
= (4x+3)(8x-6-4x-3)
= (4x+3)(4x-9)
= 16x^2 - 36x + 12x - 27
= 16x^2 - 24x - 27
not saying the second way is any easier, just another way to show it
we usually write it this way
2(4x + 3)(4x - 3) - (4x + 3)^2
= 2(16x^2 - 9) - (4x + 3)(4x + 3)
= 2(16x^2 - 9) - (16x^2 + 24x + 9)
= 32x^2 - 18 - 16x^2 - 24x - 9
= 16x^2 24x - 27
or you could take out a common factor from
2(4x + 3)(4x - 3) - (4x + 3)^2
= (4x + 3)(2(4x-3) - (4x+3))
= (4x+3)(8x-6-4x-3)
= (4x+3)(4x-9)
= 16x^2 - 36x + 12x - 27
= 16x^2 - 24x - 27
not saying the second way is any easier, just another way to show it
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