Asked by anoneemose
Given the probability of rain on any given day in March is 1/5, find the probablity that: It rains on March 10 and 12, but not on March 11th. This is supposed to be used with multiplication Rule 1:
P(A and B)= P(A)*P(B) cant figure it out, the answer is 4/125 and I have no clue how
P(A and B)= P(A)*P(B) cant figure it out, the answer is 4/125 and I have no clue how
Answers
Answered by
anoneemose
I figured this out:
1/5 = rain
4/5= no rain
1/5*1/5*4/5 = 4/125
1/5 = rain
4/5= no rain
1/5*1/5*4/5 = 4/125
Answered by
Reiny
you want:
rain, no rain, rain
= (1/5)(4/5)(1/5) = 4/125
rain, no rain, rain
= (1/5)(4/5)(1/5) = 4/125
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