Asked by calculus
f(x,y) = 3x + 3y
Show that for any epsilon in:
|2x + 3y - 5| < epsilon
There is a delta value:
sqrt((x - 1)^2 + (y - 1)^2) < delta
Solve for delta in terms of epsilon
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I understand that this is a proof that the limit of f(x,y) as (x,y) -> (1,1) is 5.
But I'm stuck solving for delta in terms of epsilon.
thanks!
Show that for any epsilon in:
|2x + 3y - 5| < epsilon
There is a delta value:
sqrt((x - 1)^2 + (y - 1)^2) < delta
Solve for delta in terms of epsilon
------
I understand that this is a proof that the limit of f(x,y) as (x,y) -> (1,1) is 5.
But I'm stuck solving for delta in terms of epsilon.
thanks!
Answers
Answered by
calculus
Sorry, f(x,y) = 2x+3y, not 3x+3y
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