Asked by Deepa( Exam prep question)
The average atomic mass of iridium is 192.22u, if iridium-191 has an atomic mass of 190.961u and an isotopic abundance of 37.3% and iridium-193 is the only other natural occuring isotope, what is the atomic mass of iridium-193?
I tried but I don't think I have the right answer..(I get 12.01???
Please help I have an exam today
I tried but I don't think I have the right answer..(I get 12.01???
Please help I have an exam today
Answers
Answered by
Steve
Surely not 12.01 -- That's carbon.
.373*190.96 + .627x = 192.22
x = 192.97
Hence the Ir-193 moniker
.373*190.96 + .627x = 192.22
x = 192.97
Hence the Ir-193 moniker
Answered by
Deepa( Exam prep question)
where did u get 627 from?
Answered by
Steve
There are only two isotopes. If Ir-191 is 37.3%, Ir-193 is 62.7%
Think back back back to Algebra I. This is just a mixture problem.
Think back back back to Algebra I. This is just a mixture problem.
Answered by
Deepa( Exam prep question)
oh 100-37.3 okokok thxx
Answered by
Benita
The answer is simple:
To get the isotopic abundance of iridium 193, you subtract the isotopic abundance of iridium 191 from 100.
Then, you substitute the formula with the figures to get:
192.22U= (190.961* 0.373) + (0.627*m2)
If you calculate accurately, you get 121/0.627 = m2
And that gave me, 192.9U
To get the isotopic abundance of iridium 193, you subtract the isotopic abundance of iridium 191 from 100.
Then, you substitute the formula with the figures to get:
192.22U= (190.961* 0.373) + (0.627*m2)
If you calculate accurately, you get 121/0.627 = m2
And that gave me, 192.9U
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