Asked by Bradley
expression in lowest terms
5(y-1)/(y-1)(y-4)
=5/y-4
5(y-1)/(y-1)(y-4)
=5/y-4
Answers
Answered by
drwls
It looks like you have already done so correctly, except for omitting some important parentheses..
5(y-1)/[(y-1)(y-4)] = 5/(y-4)
5(y-1)/[(y-1)(y-4)] = 5/(y-4)
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