Asked by Tim
Can someone tell me if I am right?
Factor by group
20x^2-12x=15x-9
20x^2+3x+9
(4x+3)(5x-3) answer
Factor by group
20x^2-12x=15x-9
20x^2+3x+9
(4x+3)(5x-3) answer
Answers
Answered by
Chaz
20x^2-27x-9
Answered by
Chaz
meant +9 and then do the rest.
Answered by
Reiny
yes, you are right, but you should have maintained your equation.
20x^2+3x+9 = 0
(4x+3)(5x-3) = 0
You could have tested your answer by expanding it to get back the
20x^2+3x+9 = 0
20x^2+3x+9 = 0
(4x+3)(5x-3) = 0
You could have tested your answer by expanding it to get back the
20x^2+3x+9 = 0
Answered by
Reiny
oops, just looked at your second line and assumed you would have had that one correct,
Chad is correct above.
Chad is correct above.
Answered by
Tim
So my second line should be:
20x^2-27x+9=0
20x^2-27x+9=0
Answered by
Reiny
yes, and it factors to
(5x-3)(4x-3) = 0
test the answer by expanding it
(5x-3)(4x-3) = 0
test the answer by expanding it
Answered by
Tim
Sorry, I put and = when it should have been a +! Is the one below right?
20x^2-12x+15x-9
20x^2-12x+15x-9
= 20x^2+3x-9
= (4x+3)(5x-3)
20x^2-12x+15x-9
20x^2-12x+15x-9
= 20x^2+3x-9
= (4x+3)(5x-3)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.