Asked by Michelle Summer
8x^3 + 27 factor the sum or difference of two cubes. Please show work.
Answers
Answered by
Reiny
You must know that
A^3 + B^3 = (A+B)(A^2 - AB + b^2)
so 8x^3 + 27)
= (2x + 3)(4x^2 - 6x + 9)
A^3 + B^3 = (A+B)(A^2 - AB + b^2)
so 8x^3 + 27)
= (2x + 3)(4x^2 - 6x + 9)
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