Asked by Rachael
Two ships sail from the same port. The first ship leaves port at 1:00a, and travels eastward at a rate of 15 knots. the second ship leave port at 2:00am and travels northward at a rate of 10 knots. Determine the rate at which the ships are separating at 3:00am
Answers
Answered by
Steve
the distance d between the ships is
d^2 = x^2 + y^2
2d dd/dt = 2x dx/dt + 2y dy/dt
at 3:00 am, x=30 and y=10, d=10√10
20√10 dd/dt = 2(30)(15) + 2(10)(10)
dd/dt = 1100/10√10 = 110/√10 = 11√10
d^2 = x^2 + y^2
2d dd/dt = 2x dx/dt + 2y dy/dt
at 3:00 am, x=30 and y=10, d=10√10
20√10 dd/dt = 2(30)(15) + 2(10)(10)
dd/dt = 1100/10√10 = 110/√10 = 11√10
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.