Asked by Anonymous
The areas of the the three adjacent faces of a cuboid are 600 sq.cm 300sq.cm and 200 sq.cm.find the sum of the length,breadth and height of the cuboid ?
Answers
Answered by
Reiny
let the dimensions be a , b, and c cm
ab=600
ac=300
bc=200
from ab=600 , b =600/a
from ac=300 , c = 300/a
from bc = 200
(600/a)(300/a) = 200
180000/a^2 = 200
200a^2 = 180000
a^2 = 900
a = 30
then b=300/30 = 20
and c = 300/30 = 10
the cuboid is 30 cm by 20 cm by 10 cm
ab=600
ac=300
bc=200
from ab=600 , b =600/a
from ac=300 , c = 300/a
from bc = 200
(600/a)(300/a) = 200
180000/a^2 = 200
200a^2 = 180000
a^2 = 900
a = 30
then b=300/30 = 20
and c = 300/30 = 10
the cuboid is 30 cm by 20 cm by 10 cm
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