t = 2.8min * 60s/min = 168 s.
d = Vo*t + 0.5a*t^2 = 3300 m.,
6.9*168 + 0.5a*(168)^2 = 3300
1159 + 14112a = 3300
14112a = 3300-1159 = 2141
a = 0.152 m/s^2.
V = Vo + at = 6.9 + 0.152*168=25.5 m/s.
A car enters the freeway with a speed of 6.9
m/s and accelerates uniformly for 3.3 km in
2.8 min.
How fast is the car moving after this time?
Answer in units of m/s
2 answers
oops! It is Henry Not anonymous.
3 answers