solve:

4x + 6y = 1/8 and 3x + 7y = 1/10

1 answer

4 x + 6 y = 1 / 8

-

3 x + 7 y = 1 / 10
_________________________

x - y = 1 / 8 - 1 / 10

x - y = 5 / 40 - 4 / 40

x - y = 1 / 40 Add y to both sides

x - y + y = 1 / 40 + y

x = y + 1 / 40

4 x + 6 y = 1 / 8

4 ( y + 1 / 40 ) + 6 y = 1 /8

4 y + 4 / 40 + 6 y = 1 / 8

10 y + 1 / 10 = 1 / 8 Subtract 1 / 10 to both sides

10 y + 1 / 10 - 1 / 10 = 1 / 8 - 1 / 10

10 y = 5 / 40 - 40 / 40

10 y = 1 / 40 Dvide both sides by 10

y = 1 / 400

x = y + 1 / 40

x = 1 / 400 + 1 / 40

x = 1 / 400 + 10 / 400

x = 11 / 400

Solutions :

x = 11 / 400

y = 1 / 400

Proof :

3 x + 7 y = 1 / 10

3 * 11 / 400 + 7 * 1 / 400 = 1 / 10

33 / 400 + 7 / 400 = 1 / 10

40 / 400 = 1 / 10

1 / 10 = 1 / 10
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