Asked by prudhvi
a body of mass 5kg initially at rest is subjected to a force of 20N. find the kinetic energy acquired by the body at the end of 10s.
Answers
Answered by
drwls
It will accelerate at a rate
a = (F/M) = 20/5 = 4 m/s^2.
After t = 10 s, the speed will be
V = a*t = 40 m/s.
Compute the kinetic energy at that time
(1/2) M V^2 = ___ Joules
a = (F/M) = 20/5 = 4 m/s^2.
After t = 10 s, the speed will be
V = a*t = 40 m/s.
Compute the kinetic energy at that time
(1/2) M V^2 = ___ Joules
Answered by
s.saitejah
2000 joules
Answered by
saimouni
4000 joules
1/2*5*(40*40)=4000joules
1/2*5*(40*40)=4000joules
Answered by
sheila
m=5kg
F=20N
u=0
t=10s
v=0
acceleration,a=F/m=20/5=4m/s2
v=u+at
v=0+4*10=40m/s
ke=1/2mv2
=1/2*5*40*40
=4000J
F=20N
u=0
t=10s
v=0
acceleration,a=F/m=20/5=4m/s2
v=u+at
v=0+4*10=40m/s
ke=1/2mv2
=1/2*5*40*40
=4000J
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