Asked by Kiki
Find three consecutive intergers such that the product of the first and the second is two more than three times the third.
Answers
Answered by
inmbi
suppose no are
x, x+1, x+2
Equal to condition
{(x)*(x+1)}=3(x+2)+2
-> x^2+x =3x+6+2
-> x^2-2x-8=0
-> x= 4 and -2
so no are 4, 5 and 6
x, x+1, x+2
Equal to condition
{(x)*(x+1)}=3(x+2)+2
-> x^2+x =3x+6+2
-> x^2-2x-8=0
-> x= 4 and -2
so no are 4, 5 and 6
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