Asked by Krissy
I have a few more questions that I'm not understanding. Its multiple choice however I would appreciate a breakdown on how to solve.
4.Simplify the compound rational expression. Use either method. 1+(5/y-10)/y+(25/y-10)
a. 1/y-5
b. 1/y+5
c. 6/y+25
d. 1/y+1/5
5.Simplify the compound rational expression. Use either method. (2/a-1/3)/(4/a^2-1/9)
a. A+3/3
b. A-3/3
c. 3A/6+A
d. 3a/6-a
7.Use the properties of exponents to simplify the expression. Write the answer using positive exponents only
-4x^0+(-4x)^0
a. 0
b. -8
c. -2
d. -3
8.Evaluate (2x-4y)^2 given x=3 and y=-1.
a. 100
b. 20
c. 4
d. -4
4.Simplify the compound rational expression. Use either method. 1+(5/y-10)/y+(25/y-10)
a. 1/y-5
b. 1/y+5
c. 6/y+25
d. 1/y+1/5
5.Simplify the compound rational expression. Use either method. (2/a-1/3)/(4/a^2-1/9)
a. A+3/3
b. A-3/3
c. 3A/6+A
d. 3a/6-a
7.Use the properties of exponents to simplify the expression. Write the answer using positive exponents only
-4x^0+(-4x)^0
a. 0
b. -8
c. -2
d. -3
8.Evaluate (2x-4y)^2 given x=3 and y=-1.
a. 100
b. 20
c. 4
d. -4
Answers
Answered by
Reiny
4. none of the choices are correct
proof: let y = 1
1+(5/y-10)/y+(25/y-10) = 1 + (-5) + 5 = 1
none of the choices produce 1
perhaps you have the brackets incorrect
e.g perhaps the first bracket of (5/y-10)
could have been (5/(y-10) )
5. same thing in this one
you have a+3/3
why didn't they just say a + 1 ?
or was it (a+3)/3
Hard to second-guess
7. -4x^0+(-4x)^0
remember, (anything)^0 = 1
= -4(1) + 1 = -3
8. (2x-4y)^2 , when x=3, y=-1
= (6 + 4)^2
= 10^2
= 100
proof: let y = 1
1+(5/y-10)/y+(25/y-10) = 1 + (-5) + 5 = 1
none of the choices produce 1
perhaps you have the brackets incorrect
e.g perhaps the first bracket of (5/y-10)
could have been (5/(y-10) )
5. same thing in this one
you have a+3/3
why didn't they just say a + 1 ?
or was it (a+3)/3
Hard to second-guess
7. -4x^0+(-4x)^0
remember, (anything)^0 = 1
= -4(1) + 1 = -3
8. (2x-4y)^2 , when x=3, y=-1
= (6 + 4)^2
= 10^2
= 100
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