Question
a ball is dropped from a height of 10 ft. if the ball's height after t sec is modeled by the following equation h(t)=-16t^2+10. when does the ball hit the ground?
Answers
Reiny
when it hits the ground, h(t) = 0
0 = -16t^2 + 10
16t^2 = 10
t^2 = 10/16
t = √10/4 or appr .79 seconds
0 = -16t^2 + 10
16t^2 = 10
t^2 = 10/16
t = √10/4 or appr .79 seconds