Solve the equation sin2x=2cos2x, for 0 degrees <=x<=180 degrees

2 answers

Divide both sides by cos2x.
You will get:
tan2x = 2

2x = 63.435 degrees or 243.435 degrees
x = 31.72 degrees or 121.72 degrees
Sin2x=2cos2x
Diving both sides by cos2x,we get
tan2x=2
Then, what's tan2x?
It's ; 2tanx/1-tan²x =2
Cross multiply,we get
-2tan²x+2tanx+2=o
Diving by 2 the entire equation,
-Tan²x+tanx+1=0
That's where I got stuck from 😢
Similar Questions
  1. f(x) = x² + 2Cos²x, find f ' (x)a) 2(x+cos x) b) x - sin x c) 2x + sin x d)2(x - sin2x) I got neither of these answers, since
    1. answers icon 3 answers
  2. Solve the equation 2cos2x = √3 for 0°≤x≤360°I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct?
    1. answers icon 1 answer
  3. what is the exact value of1-2sin(15degrees)? also 2(sin2x)=2sinx solve it for 0<_x_<360 and also 2cos2x=-�ã3 solve it and find
    1. answers icon 2 answers
  4. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
    1. answers icon 4 answers
more similar questions