Asked by Anonymous

log base b 64 - log base b 16 = log base 4 16
solve for the variable..

i got to the part as far as:

(log 4/log b) = 2

now i m stuck at how i can isolate the b. plz help!
Answered by Reiny
look at your right side
isn't log<sub>4</sub> 16 = 2 ???

so you have:
log<sub>b</sub> 64 - log<sub>b</sub>16 = 2
log<sub>b</sub>(64/16) = 2
log<sub>b</sub> 4 = 2
or
b^2 = 4
b = 2

from your:

log4/logb = 2
cross-multiply
log4 = 2logb
log4 = log b^2
then 4 = b^2
b = 2 , just like above
Answered by Damon
log b (4) = 2

b^log b( 4) = 4

so b^logb(4) = b^2
so
b^2 = 4

b = 2

Answered by Anonymous
Ohh alright! Thank you :)
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