Question
A valid Lewis structure of __________ cannot be drawn without violating the octet rule.
Answer: BeH2
Why would BeH2 break the octet?
Answer: BeH2
Why would BeH2 break the octet?
Answers
Is it because it only has four electrons to begin with with only two valence electrons? There's no way it can possible even make an octet?
Yes but BeH2 is not that common. I think BeCl2 is a better example. Boron is another that breaks the octet rule; e.g., BF3.
Be and B are the huge ones on breaking the octet rule. But, for that question they gave BeH2 so, I guess reasoning is that they are the exceptions? It's multiple choice. but I still want to understand it.
H:Be:H
Related Questions
The instructions are, Write Lewis structures that obey the octet rule for the following species. (As...
Chemical bonding question!
The partial Lewis structure that follows (Figure 1) is for a hydrocarb...
Explain why BF3 does not follow the octet rule.
B is surrounded by only _______________electrons...
Explain why BF3 does not follow the octet rule.
B is surrounded by only _______________electrons...