Asked by Anon

A valid Lewis structure of __________ cannot be drawn without violating the octet rule.
Answer: BeH2
Why would BeH2 break the octet?
Answered by Anon
Is it because it only has four electrons to begin with with only two valence electrons? There's no way it can possible even make an octet?
Answered by DrBob222
Yes but BeH2 is not that common. I think BeCl2 is a better example. Boron is another that breaks the octet rule; e.g., BF3.
Answered by Anon
Be and B are the huge ones on breaking the octet rule. But, for that question they gave BeH2 so, I guess reasoning is that they are the exceptions? It's multiple choice. but I still want to understand it.
Answered by DrBob222
H:Be:H
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