A valid Lewis structure of __________ cannot be drawn without violating the octet rule.

Question

A valid Lewis structure of __________ cannot be drawn without violating the octet rule. 
Answer: BeH2
Why would BeH2 break the octet?

Anon · Answer

Is it because it only has four electrons to begin with with only two valence electrons? There's no way it can possible even make an octet?

DrBob222 · Answer

Yes but BeH2 is not that common. I think BeCl2 is a better example. Boron is another that breaks the octet rule; e.g., BF3.

Anon · Answer

Be and B are the huge ones on breaking the octet rule. But, for that question they gave BeH2 so, I guess reasoning is that they are the exceptions? It's multiple choice. but I still want to understand it.

DrBob222 · Answer

H:Be:H