Asked by Anonymous
An electron moving at a speed of 5 multiply by 10 raise to power six m/s was shot through a sheet of paper which is 2.1 multiply by 4cm thick.the electron emerges from the paper with a speed of 2 multiply by 10 raise to power six m/s,find the time taken by the electron to pass through the sheet.
Answers
Answered by
Jennifer
vf - vi = 5*10^6 - 2*10^6 = 3*10^6
where vf is the final speed and vi is the initial speed.
Assuming a constant deceleration, the electron passes through 2.1 multiply 4cm = 8.4 cm of paper.
8.4 = 1/2*a*t^2
deltav = 3*10^6 = a*t
where a is the acceleration, t is the time. You have two equations with two unkowns (a and t). Use algebra to solve for t, the time taken by the electron to pass through the sheet.
where vf is the final speed and vi is the initial speed.
Assuming a constant deceleration, the electron passes through 2.1 multiply 4cm = 8.4 cm of paper.
8.4 = 1/2*a*t^2
deltav = 3*10^6 = a*t
where a is the acceleration, t is the time. You have two equations with two unkowns (a and t). Use algebra to solve for t, the time taken by the electron to pass through the sheet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.