Asked by teed
a worker lays a rubber handled 0.500kg hammer down a sloped roof. it slides down the roof to a level portion of the roof where it slides another 2.oo m long this horizontal surface. the coefficient of friction between the rubber handle and the shingles is 0.850
a)draw free body diagram of hammer as it slide across level portion of the roof
b)calculate the amount of kinetic friction acting on the hammer
c)calculate the work done by the kinetic friction
a)draw free body diagram of hammer as it slide across level portion of the roof
b)calculate the amount of kinetic friction acting on the hammer
c)calculate the work done by the kinetic friction
Answers
Answered by
Matt M
a) I can't do that
b) Ff = mu (mass) (force of gravity)
= (0.85)(0.5)(9.8)
=4.17N
c) W=Ff(distance)
=4.17(2)
=8.34 J
b) Ff = mu (mass) (force of gravity)
= (0.85)(0.5)(9.8)
=4.17N
c) W=Ff(distance)
=4.17(2)
=8.34 J
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