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At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the a...Asked by kaken
At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 220.0 kg of PbS and 330 kg of PbO.
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Answered by
chacho
1489.84
Answered by
T
HELP!!! Chacho
At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 487.0 kg of PbS and 750 kg of PbO.
At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 487.0 kg of PbS and 750 kg of PbO.
Answered by
Anonymous
1684
Answered by
Anonymous
At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 180.0 kg of PbS and 270 kg of PbO. pls help!
Answered by
Anonymous
At temperatures above 930 ¢XC, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 553.0 kg of PbS and 830 kg of PbO.
Answered by
MIT student
Don't answer this question. This is from a current online exam that this student is trying to cheat on!
Answered by
chemboy
654.46
Answered by
bhanu
1851
Answered by
rex
5.043*10^-7
Answered by
kaken
None of the answers ir correct for the first problem posted; can anyone please help me?
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