Asked by Chemgam
(a) What is the distance between second nearest neighbor atoms in vanadium? Express your answer in cm.
(b) What is the interplanar spacing between (110) planes in vanadium? Express your answer in cm.
(c) At what angle must (110) planes of vanadium be exposed to a collimated beam of X-rays in order to obtain diffraction by monochromatic chromium K-alpha radiation? Express your answer in degrees.
(b) What is the interplanar spacing between (110) planes in vanadium? Express your answer in cm.
(c) At what angle must (110) planes of vanadium be exposed to a collimated beam of X-rays in order to obtain diffraction by monochromatic chromium K-alpha radiation? Express your answer in degrees.
Answers
Answered by
Anonymous
a) 3.03⋅10−8
Answered by
lena
something wrong ..
Answered by
Anonymous
b) 2.14*10^-8
Answered by
c
pls. c
Answered by
qpt
a)3.03*10^-8
b) 2.14*10^-8
any ideas for c)?
b) 2.14*10^-8
any ideas for c)?
Answered by
chemboy
c) 33.2
Answered by
Anonymous
3.2e-8
Answered by
Chemgam
Thank you
a)3.03*10^-8
b) 2.14*10^-8
c) 33.2
a)3.03*10^-8
b) 2.14*10^-8
c) 33.2
Answered by
Anonymous
a is qrong can you please teach me how to do this