Asked by zamarra
how to factor (2a+3b)^2-4c(2a+3b)+4c2
Answers
Answered by
drwls
Let 2a + 3b = d
Then it becomes
d^2 -4cd + 4c^2 = (d-2c)^2
Therefore it factors as
(2a + 3b -2c)^2
Then it becomes
d^2 -4cd + 4c^2 = (d-2c)^2
Therefore it factors as
(2a + 3b -2c)^2
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