Question
molar enthalpy of combustion for pentane?
Mass C5H12= 2.15g
Mass H2O= 1.24kg
Initial temp= 18.4°C
Final temp= 37.6°C
Mass C5H12= 2.15g
Mass H2O= 1.24kg
Initial temp= 18.4°C
Final temp= 37.6°C
Answers
DrBob222
Is this in a bomb calorimeter or some other apparatus?
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
delta H/g = q/2.15
delta H/mol = (q/2.15)*molar mass pentane
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
delta H/g = q/2.15
delta H/mol = (q/2.15)*molar mass pentane