Asked by Lizzy
The pH of a solution of Sr(OH)2 is 12.42. What is its (OH^-)
Answers
Answered by
DrBob222
Use pH + pOH = pKw = 14 You know pH, solve for pOH, then
pOH = -log(OH^-).
Substitute and solve for OH^-.
pOH = -log(OH^-).
Substitute and solve for OH^-.
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