Question

Before 1986, a gold bullion in the Federal Reserve Bank was rectangular and had a volume of approximately 727.7 cm3. The density of gold is 19.3 g/cm3. A pound is approximately 454 g. Find the weight of one gold bullion to the nearest tenth of a pound.

Answers

Bob
Explanation please
Mr56people
31
Anonymous
305 lbs.
Pranav
30
Bone Hoody
315
vhv
hfh
JUSOOKY
30.9 lb
MS
Mass = Density X Volume
Mass = 727.7 CM^3 X 19.3 g/cm^3
Mass = 14,044.61 g
Since a pound is approximately 454 g

Mass = 14,044.61/454
Mass/weight = 30.9 lbs

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