Asked by Bob

Before 1986, a gold bullion in the Federal Reserve Bank was rectangular and had a volume of approximately 727.7 cm3. The density of gold is 19.3 g/cm3. A pound is approximately 454 g. Find the weight of one gold bullion to the nearest tenth of a pound.
Answered by Bob
Explanation please
Answered by Mr56people
31
Answered by Anonymous
305 lbs.
Answered by Pranav
30
Answered by Bone Hoody
315
Answered by vhv
hfh
Answered by JUSOOKY
30.9 lb
Answered by MS
Mass = Density X Volume
Mass = 727.7 CM^3 X 19.3 g/cm^3
Mass = 14,044.61 g
Since a pound is approximately 454 g

Mass = 14,044.61/454
Mass/weight = 30.9 lbs
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