Asked by Bob
Before 1986, a gold bullion in the Federal Reserve Bank was rectangular and had a volume of approximately 727.7 cm3. The density of gold is 19.3 g/cm3. A pound is approximately 454 g. Find the weight of one gold bullion to the nearest tenth of a pound.
Answers
Answered by
Bob
Explanation please
Answered by
Mr56people
31
Answered by
Anonymous
305 lbs.
Answered by
Pranav
30
Answered by
Bone Hoody
315
Answered by
vhv
hfh
Answered by
JUSOOKY
30.9 lb
Answered by
MS
Mass = Density X Volume
Mass = 727.7 CM^3 X 19.3 g/cm^3
Mass = 14,044.61 g
Since a pound is approximately 454 g
Mass = 14,044.61/454
Mass/weight = 30.9 lbs
Mass = 727.7 CM^3 X 19.3 g/cm^3
Mass = 14,044.61 g
Since a pound is approximately 454 g
Mass = 14,044.61/454
Mass/weight = 30.9 lbs
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