Asked by beth
what is the frezzing point of 21.6 grams of NiSO4 in 1.00 times 10^2 H2O
Answers
Answered by
DrBob222
1.00 times 10^2 WHAT of H2O?
mols NiSO4 = grams/molar mass.
molality = m NiSO4 = mols/kg solvent.
Tnen delta T = i*Kf*m
i = 2 for NiSO4. You know Kf and m, solve for delta T.
Finally, subtract delta T from the normal freezing point to find the new freezing point.
mols NiSO4 = grams/molar mass.
molality = m NiSO4 = mols/kg solvent.
Tnen delta T = i*Kf*m
i = 2 for NiSO4. You know Kf and m, solve for delta T.
Finally, subtract delta T from the normal freezing point to find the new freezing point.
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