V(cos(theta))=12
V=12/sec40deg
A baseball is thrown at an angle of 40.0° above
the horizontal. The horizontal component of the
baseball’s initial velocity is 12.0 meters per
second. What is the magnitude of the ball’s initial
velocity?
4 answers
oops V=12/cos40deg
isn't the degree of 40 already given though? Why don't you do 12sin40?
sine would give you the vertical compnent, horizontal component is cosine times velocity
0 answers