Asked by Gloria
When 50.0g of silicon dioxide is heated with an excess of carbon 32.2 g of silicon carbide I'd produced.
SiO2(s) + 3C(s) → SiC(s) + 2CO(g)
A. What is the percent yield of this reaction?
B. How many grams of CO gas are made?
SiO2(s) + 3C(s) → SiC(s) + 2CO(g)
A. What is the percent yield of this reaction?
B. How many grams of CO gas are made?
Answers
Answered by
DrBob222
Convert 50 g SiO2 to mols. mols = grams/molar mass.
Using the coefficients in the balance chemical equation convert moles SiO2 to SiC.
Convert moles SiC to grams. g = mols x molar mass. This is the theoretical yield.
Percent yield = (actual yield/theoretical yield)*100 = ?
Part B is in the same way as part A. Post your work if you get stuck.
Using the coefficients in the balance chemical equation convert moles SiO2 to SiC.
Convert moles SiC to grams. g = mols x molar mass. This is the theoretical yield.
Percent yield = (actual yield/theoretical yield)*100 = ?
Part B is in the same way as part A. Post your work if you get stuck.
Answered by
Anonymous
.97
Answered by
Laquisha ingram
The answer is 17
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