Question

This is a 8th grade question:
Given C+C=D, D+E=17, A+2C=D, and 2B+C=8, what is the value of A+B+C+D???
Can you also show how you got it?

Answer 1

To start, if C+C=D and A+2C = D, then A = 0.

With E and B being only in one equation each, I can't figure out how to solve for B, C or D. Do you have any typos?

Answer 2

Eq1 and 3. 2C=D,A=0. Eq2 and 4.C=O,B=4,D=0,E=17.Therefore A+B+C+D=21