Asked by Anonymous
The sun of the first five terms of a geometric series is 186 and the sum of the first six terms is 378. if the fourth term is 48, determine a,r, t10, S10
Answers
Answered by
PJ
The sun of the first five terms of a geometric series is 186 and the sum of the first six terms is 378. if the fourth term is 48, determine a,r, t10, S10
Answered by
Steve
Since S6 = S5 + T6,
378 = 186 + T6
T6 = 192
T6 = T4*r^2
192 = 48r^2
r^2=4
r=2
T4 = ar^3
48 = 8a
a = 6
Sequence is thus
6, 12, 24, 48, 96, 192, ...
T10 = 6*2^9 = 3072
S10 = 6*(1023) = 6138
378 = 186 + T6
T6 = 192
T6 = T4*r^2
192 = 48r^2
r^2=4
r=2
T4 = ar^3
48 = 8a
a = 6
Sequence is thus
6, 12, 24, 48, 96, 192, ...
T10 = 6*2^9 = 3072
S10 = 6*(1023) = 6138
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