Asked by Rosa
If, in the reaction below, 31 g of C4H10 produces 41 41 g of CO2, what is the percent yield? Assume that the one reactant is limiting. 2C4H10 + 13O2 + 10H2O
Answers
Answered by
DrBob222
Did you make a typo? Is that 41 g, 41.41, or some other number? I know you made a typo in the reaction.
#1. There is no arrow.
#2. There is no CO2 shown.
Balance the equation.
2C4H10 + 13O2 ==> 8CO2 + 10H2O.
mols C4H10 = grams/molar mass.
Using the coefficients in the balanced equation, convert mols C4H10 to mols CO2.
Convert mols CO2 to g. grams = mols x molar mass. This is the theoretical yield.
%yield (actual grams CO2/theoretical yield)*100 =
#1. There is no arrow.
#2. There is no CO2 shown.
Balance the equation.
2C4H10 + 13O2 ==> 8CO2 + 10H2O.
mols C4H10 = grams/molar mass.
Using the coefficients in the balanced equation, convert mols C4H10 to mols CO2.
Convert mols CO2 to g. grams = mols x molar mass. This is the theoretical yield.
%yield (actual grams CO2/theoretical yield)*100 =
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.